Asked by Phillip
The numbers -3, -4, and 6 are used once and substitued at random for a, b, and c in the equation ax+b=c. What is the probability that x turns out to be negative.
I'm not sure where to begin with this. Can you help?
I'm not sure where to begin with this. Can you help?
Answers
Answered by
drwls
First solve for x.
x = (c-b)/a
Then make a table of all possible a,b, c permutations and calculate the corresponding x.
a b c x
_____________
-3.-4. 6..-10/3
-3. 6. -4.. 10/3
-4.-3...6.. -9/4
-4..6..-3.. 9/4
6..-3..-4.. -1/6
6..-4..-3.. 1/6
Half of the possibilties lead to a positive value of x.
x = (c-b)/a
Then make a table of all possible a,b, c permutations and calculate the corresponding x.
a b c x
_____________
-3.-4. 6..-10/3
-3. 6. -4.. 10/3
-4.-3...6.. -9/4
-4..6..-3.. 9/4
6..-3..-4.. -1/6
6..-4..-3.. 1/6
Half of the possibilties lead to a positive value of x.
Answered by
Phillip
ahhhhhh thanks!
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