To divide the polynomial \( 18x^2 + 9x + 3 \) by \( -3x \), we can perform polynomial long division or simply divide each term of the polynomial by \( -3x \).
Let's divide each term of \( 18x^2 + 9x + 3 \) by \( -3x \):
- \( \frac{18x^2}{-3x} = -6x \)
- \( \frac{9x}{-3x} = -3 \)
- \( \frac{3}{-3x} = -\frac{1}{x} \)
Putting it all together, we get:
\[ \frac{18x^2 + 9x + 3}{-3x} = -6x - 3 - \frac{1}{x} \]
Therefore, the correct response from the options provided is:
\(-6x - 3 - \frac{1}{x}\) (which corresponds to "−6x−3−1x").