To simplify the expression \( \frac{150 \cdot 7^{-2}}{(-4)^{-3}} \), we will apply the properties of integer exponents stepwise.
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Rewrite the expression while moving the negative exponents to the denominator: \[ \frac{150 \cdot 7^{-2}}{(-4)^{-3}} = 150 \cdot \frac{1}{7^2} \cdot (-4)^3 = \frac{150 \cdot (-4)^3}{7^2} \]
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Now, calculating \( (-4)^3 \): \[ (-4)^3 = -64 \]
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So, we replace \( (-4)^3 \) in the expression: \[ = \frac{150 \cdot (-64)}{7^2} \]
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Converting this to a fraction, we can simplify it: \[ = \frac{-9600}{49} \]
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At this point, all the exponents are positive since we have \( 7^2 \) in the denominator and a positive base for \( 4 \).
Now, checking the choices provided:
- 172 ⋅ (−4)−3 - This has a negative exponent.
- Start Fraction 1 over 7 squared times left parenthesis negative 4 right parenthesis superscript negative 3 baseline End Fraction - This has negative exponents.
- 72(−4)3 - This has no negative exponents but does not reflect the original expression's equivalence correctly.
- Start Fraction 7 squared over left parenthesis negative 4 right parenthesis cubed end fraction - This has negative in the denominator.
- (−4)372 - This has negative exponents and doesn't capture the conversion correctly.
- 4^3/7^2 - This presents only positive exponents.
Therefore, the equivalent expression to \( \frac{150 \cdot 7^{-2}}{(-4)^{-3}} \) with only positive exponents is:
4^3/7^2