To simplify the expression \( \frac{150 \cdot 7^{-2}}{(-4)^{-3}} \), we will apply the properties of integer exponents stepwise.
1. Rewrite the expression while moving the negative exponents to the denominator:
\[
\frac{150 \cdot 7^{-2}}{(-4)^{-3}} = 150 \cdot \frac{1}{7^2} \cdot (-4)^3 = \frac{150 \cdot (-4)^3}{7^2}
\]
2. Now, calculating \( (-4)^3 \):
\[
(-4)^3 = -64
\]
3. So, we replace \( (-4)^3 \) in the expression:
\[
= \frac{150 \cdot (-64)}{7^2}
\]
4. Converting this to a fraction, we can simplify it:
\[
= \frac{-9600}{49}
\]
5. At this point, all the exponents are positive since we have \( 7^2 \) in the denominator and a positive base for \( 4 \).
Now, checking the choices provided:
1. **172 ⋅ (−4)−3** - This has a negative exponent.
2. **Start Fraction 1 over 7 squared times left parenthesis negative 4 right parenthesis superscript negative 3 baseline End Fraction** - This has negative exponents.
3. **72(−4)3** - This has no negative exponents but does not reflect the original expression's equivalence correctly.
4. **Start Fraction 7 squared over left parenthesis negative 4 right parenthesis cubed end fraction** - This has negative in the denominator.
5. **(−4)372** - This has negative exponents and doesn't capture the conversion correctly.
6. **4^3/7^2** - This presents only positive exponents.
Therefore, the equivalent expression to \( \frac{150 \cdot 7^{-2}}{(-4)^{-3}} \) with only positive exponents is:
**4^3/7^2**