Question
Which function, h of x, results when f of x equals 2 x squared minus 6 is subtracted from g of x equals 2 x squared plus 5 x minus 1?
Answer options with 5 options
A.
h of x equals 5 x plus 5
B.
h of x equals 5 x minus 7
C.
h of x equals negative 5 x minus 5
D.
h of x equals x squared plus 5 x minus 7
E.
h of x equals 4 x squared plus 5 x minus 7
Answer options with 5 options
A.
h of x equals 5 x plus 5
B.
h of x equals 5 x minus 7
C.
h of x equals negative 5 x minus 5
D.
h of x equals x squared plus 5 x minus 7
E.
h of x equals 4 x squared plus 5 x minus 7
Answers
Answered by
GPT-4o mini
To find the function \( h(x) \) resulting from subtracting \( f(x) \) from \( g(x) \), we need to evaluate the expression:
\[
h(x) = g(x) - f(x)
\]
Given the functions:
- \( f(x) = 2x^2 - 6 \)
- \( g(x) = 2x^2 + 5x - 1 \)
Now, substituting these into our equation:
\[
h(x) = (2x^2 + 5x - 1) - (2x^2 - 6)
\]
Now simplifying the expression:
\[
h(x) = 2x^2 + 5x - 1 - 2x^2 + 6
\]
The \( 2x^2 \) terms cancel out:
\[
h(x) = 5x - 1 + 6
\]
\[
h(x) = 5x + 5
\]
Thus, the function \( h(x) \) is:
\[
h(x) = 5x + 5
\]
Therefore, the correct answer is:
**A. \( h(x) = 5x + 5 \)**
\[
h(x) = g(x) - f(x)
\]
Given the functions:
- \( f(x) = 2x^2 - 6 \)
- \( g(x) = 2x^2 + 5x - 1 \)
Now, substituting these into our equation:
\[
h(x) = (2x^2 + 5x - 1) - (2x^2 - 6)
\]
Now simplifying the expression:
\[
h(x) = 2x^2 + 5x - 1 - 2x^2 + 6
\]
The \( 2x^2 \) terms cancel out:
\[
h(x) = 5x - 1 + 6
\]
\[
h(x) = 5x + 5
\]
Thus, the function \( h(x) \) is:
\[
h(x) = 5x + 5
\]
Therefore, the correct answer is:
**A. \( h(x) = 5x + 5 \)**