To prove that triangles \( \triangle ABC \cong \triangle CDA \) by the ASA (Angle-Side-Angle) Congruence Theorem, we need the following information:
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Information about the angles: We have already stated that \( \angle BCA \cong \angle DAC \) and \( \angle BAC \cong \angle DCA \). These two pairs of angles provide us with two angles in each triangle.
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Additional information about the side: The side you must establish as congruent for ASA is \( AC \) since both triangles share this side. \[ AC \cong AC \quad \text{(by the Reflexive Property of Congruence)} \]
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Conclusion: With the congruence of two angles and the included side \( AC \cong AC \) established, we can conclude that: \[ \triangle ABC \cong \triangle CDA \quad \text{(by the ASA Congruence Theorem)} \]
It appears that you already have the congruences set up, but didn't explicitly state the necessary additional information about congruence of side \( AC \). Here's the summary of information needed for the proof:
- Given angles: \( \angle BCA \cong \angle DAC \) and \( \angle BAC \cong \angle DCA \).
- Shared side: \( AC \cong AC \) (Reflexive Property of Congruence).
By clarifying this information, you ensure that all necessary elements for the ASA theorem are covered, allowing you to conclude triangle congruence effectively.