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Question

Question
Two workers are pushing on the same large crate. One worker pushes east with a force of 875 N, while the other worker pushes north with a force of 960 N. Friction between the crate and the floor is directed west with a force of 80 N and south with a force of 105 N. Assuming the drag due to air resistance is negligible, what are the total north-south net forces and the total east-west net force acting on the crate, causing it to accelerate across the floor?(1 point)
Responses

795 N to the north and 855 N and to the east
795 N to the north and 855 N and to the east

855 N to the South and 759 N and to the West
855 N to the South and 759 N and to the West

855 N to the north and 795 N to the east
855 N to the north and 795 N to the east

795 N to the south and 850 N to the west
795 N to the south and 850 N to the west
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Answer 1

To find the total north-south net forces and the total east-west net forces acting on the crate, we need to sum the forces in each direction.

North-South Forces:

• Force pushing north: +960 N (from the worker)
• Force pushing south: -105 N (friction)

Net north-south force: \[ F_{NS} = 960 N - 105 N = 855 N \text{ (north)} \]

East-West Forces:

• Force pushing east: +875 N (from the worker)
• Force pushing west: -80 N (friction)

Net east-west force: \[ F_{EW} = 875 N - 80 N = 795 N \text{ (east)} \]

Now we can summarize the results:

Total north-south net force: 855 N to the north
Total east-west net force: 795 N to the east

Therefore, the response should be: 855 N to the north and 795 N to the east.