To calculate the heat solution of the copper(II) tetraoxosulphate(VI) salt when dissolved in water, we will use the equation:
q = m * c * ΔT
where:
q = heat energy (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g·°C)
ΔT = change in temperature (in °C)
First, let's calculate the mass of the copper(II) tetraoxosulphate(VI) salt:
32.0g of anhydrous copper(II) tetraoxosulphate(VI) = 32.0g
Next, convert the volume of water to grams using its density:
Density of water = 1g/cm^3
1dm^3 = 1000cm^3
4dm^3 = 4,000cm^3
mass of water = volume * density = 4,000cm^3 * 1g/cm^3 = 4,000g
The total mass of the solution = mass of copper(II) tetraoxosulphate(VI) + mass of water
= 32.0g + 4,000g = 4,032g
Next, calculate the heat energy:
q = m * c * ΔT
The specific heat capacity (c) of the solution is not given. We'll assume it's 4.18 J/g·°C, which is approximately the specific heat capacity of water.
Given that the change in temperature (ΔT) = 13.0 K (Kelvin is the same as Celsius)
q = 4,032g * 4.18 J/g·°C * 13.0°C
q = 217,513.28 J ≈ 217.5 kJ
The heat solution is approximately 217.5 kJ.
32.0g of anhydrous copper 2 tetraoxosulphate 6 dissolved to 4dm^3 of water generated 13.0k of beat,the heat solution is
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