To find the product of the polynomials \((x^2y + 2)(x^2 - y)\), we can use the distributive property (also known as the FOIL method for binomials).
Let's distribute each term in the first polynomial:
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Multiply \(x^2y\) by each term in \((x^2 - y)\):
- \(x^2y \cdot x^2 = x^4y\)
- \(x^2y \cdot (-y) = -x^2y^2\)
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Multiply \(2\) by each term in \((x^2 - y)\):
- \(2 \cdot x^2 = 2x^2\)
- \(2 \cdot (-y) = -2y\)
Now, combine all of these results: \[ x^4y - x^2y^2 + 2x^2 - 2y \]
Therefore, the product of the two polynomials is: \[ x^4y - x^2y^2 + 2x^2 - 2y \]
Looking at the responses you provided, the correct answer is: \[ \boxed{x^4y - x^2y^2 + 2x^2 - 2y} \]