1) Graph f(x) = x2−3x+2

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2) f(0) =


3) ​f(1)=

4)​f(2)=

5) The y-intercept is
. Write it as an ordered pair

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Answer 1

To analyze the function $f(x)=x^2-3x+2$, we'll calculate the values at specific points and find the y-intercept.

1. Calculate $f(0)$: $$f(0)=0^2-3(0)+2=0+0+2=2$$

2. Calculate $f(1)$: $$f(1)=1^2-3(1)+2=1-3+2=0$$

3. Calculate $f(2)$: $$f(2)=2^2-3(2)+2=4-6+2=0$$

4. Determine the y-intercept: The y-intercept occurs when $x=0$, which we've already calculated. The y-intercept is given as an ordered pair: $$\text{Y-intercept}=(0,f(0))=(0,2)$$

Summary of Results:

• $f(0)=2$
• $f(1)=0$
• $f(2)=0$
• The y-intercept is $(0,2)$