Use the polynomial identity of the difference of two squares to write a product equal to 81-16

1 answer

The difference of two squares can be expressed using the identity:

\[ a^2 - b^2 = (a - b)(a + b) \]

To apply this to the expression \(81 - 16\), we first recognize that \(81\) and \(16\) are both perfect squares:

\[ 81 = 9^2 \quad \text{and} \quad 16 = 4^2 \]

Now we can rewrite the expression \(81 - 16\) as:

\[ 81 - 16 = 9^2 - 4^2 \]

Using the difference of squares identity, we can factor this as:

\[ 9^2 - 4^2 = (9 - 4)(9 + 4) \]

Now, we calculate the two factors:

\[ 9 - 4 = 5 \] \[ 9 + 4 = 13 \]

Therefore, we can write:

\[ 81 - 16 = (9 - 4)(9 + 4) = 5 \cdot 13 \]

In conclusion, the product equal to \(81 - 16\) is:

\[ 81 - 16 = 5 \cdot 13 \]