How could the program be modified to print the product of all the even numbers less than 7?

Question

(1 point)
Responses

def factorial(n):
if n <= 1:
return 1
else:
if n % 2 != 0:
return n * factorial(n - 2)
else:
return factorial(n - 1)
print("The answer is", factorial(7))
def factorial(n): if n <= 1: return 1 else: if n % 2 != 0: return n * factorial(n - 2) else: return factorial(n - 1) print("The answer is", factorial(7))

def factorial(n):
if n <= 1:
return n
else:
return n * factorial(n - 2)
print("The answer is", factorial(7))
def factorial(n): if n <= 1: return n else: return n * factorial(n - 2) print("The answer is", factorial(7))

def factorial(n):
if n == 1:
return n
else:
return n * factorial(n - 2)
print("The answer is", factorial(7))
def factorial(n): if n == 1: return n else: return n * factorial(n - 2) print("The answer is", factorial(7))

def factorial(n):
if n == 0:
return 1
else:
if n % 2 == 0:
return n * factorial(n - 2)
else:
return factorial(n - 1)
print("The answer is", factorial(7))

Answer 1

To modify the program so that it prints the product of all the even numbers less than 7, we need to adjust the logic within the function. In this case, we want to compute the product of the even numbers specifically (i.e., 2, 4, and 6). Here's how you can do that:

def product_of_evens(n):
    if n <= 0:
        return 1
    elif n % 2 == 0:
        return n * product_of_evens(n - 2)
    else:
        return product_of_evens(n - 1)

# Calling the function with 6 because we want even numbers less than 7
print("The answer is", product_of_evens(6))

Explanation of the Code Changes:

1. The function is renamed to product_of_evens to better reflect its purpose.
2. The base case is set to return 1 when n <= 0. This ensures that if there are no even numbers to multiply (i.e., when starting with non-positive values), we return 1 (the multiplicative identity).
3. If n is even, it multiplies n by the product of evens of n - 2 (to process the next smaller even number).
4. If n is odd, it just calls the function with n - 1 to skip to the next lower even number.
5. Finally, we call the function with 6 since we want to include all even numbers less than 7.

This implementation will yield the product of all even numbers less than 7 (2, 4, and 6), which equals 48.