Let's simplify the expression step by step:
The original expression is:
\[ z + \frac{6}{3^2} - (2 \times 3) + 5 \]
1. Calculate \( 3^2 \):
\[ 3^2 = 9 \]
2. Now substituting it back in:
\[ z + \frac{6}{9} - (2 \times 3) + 5 \]
3. Simplify \( \frac{6}{9} \) (which reduces to \( \frac{2}{3} \)):
\[ z + \frac{2}{3} - (2 \times 3) + 5 \]
4. Calculate \( 2 \times 3 \):
\[ 2 \times 3 = 6 \]
5. Now substituting it back:
\[ z + \frac{2}{3} - 6 + 5 \]
6. Combine \( -6 + 5 \):
\[ -6 + 5 = -1 \]
7. Now substituting back:
\[ z + \frac{2}{3} - 1 \]
8. Rewrite \( -1 \) as \( -\frac{3}{3} \):
\[ z + \frac{2}{3} - \frac{3}{3} \]
9. Combine the fractions:
\[ z + \left(\frac{2}{3} - \frac{3}{3}\right) = z - \frac{1}{3} \]
Thus, there is no denominator for the entire expression after simplification; however, if you're asking for the denominator from the fraction \( \frac{2}{3} \) that appeared in the calculation, it's 3.
The answer choices (8 and 26) do not relate to the simplified expression \( z - \frac{1}{3} \). Could you please confirm the question, as it seems your provided options donβt match the denominator present in the calculations? If you're looking for something else, please clarify!