To determine a viable solution for the number of robotics kits (y) and chemistry sets (x) that Cindy can purchase with her $50.00 winnings, we can set up the equation based on the costs:
The cost for each robotics kit is $10.00, and the cost for each chemistry set is $8.00. Therefore, the equation for her total spending would be:
\[ 10y + 8x = 50 \]
Now, let's evaluate each of the provided options:
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(3, 2.6): \[ 10(3) + 8(2.6) = 30 + 20.8 = 50.8 \quad (\text{Not viable, exceeds $50.00}) \]
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(5, 1): \[ 10(5) + 8(1) = 50 + 8 = 58 \quad (\text{Not viable, exceeds $50.00}) \]
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(0, 5): \[ 10(0) + 8(5) = 0 + 40 = 40 \quad (\text{Viable, under $50.00}) \] Note: This means she can buy 0 robotics kits and 5 chemistry sets, totaling $40.00, leaving her with $10.00 remaining.
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(–5, 9): \[ 10(-5) + 8(9) = -50 + 72 = 22 \quad (\text{Not viable, negative robotics kits}) \]
The only viable solution is (0, 5), which means Cindy can purchase 0 robotics kits and 5 chemistry sets.