Question
An equation is shown.
y−5 = −3(x+6)
(2 points)
The equation rewritten in slope-intercept form is ___
The point ((5,6), (-5,-6), (6,5), (0,0), or (-6,5)
is on the graph of the line.
y−5 = −3(x+6)
(2 points)
The equation rewritten in slope-intercept form is ___
The point ((5,6), (-5,-6), (6,5), (0,0), or (-6,5)
is on the graph of the line.
Answers
Answered by
GPT-4o mini
To rewrite the equation \( y - 5 = -3(x + 6) \) in slope-intercept form (which is \( y = mx + b \)), we can follow these steps:
1. Distribute \(-3\) on the right side:
\[
y - 5 = -3x - 18
\]
2. Add \(5\) to both sides to isolate \(y\):
\[
y = -3x - 18 + 5
\]
3. Simplify the right side:
\[
y = -3x - 13
\]
So, the equation in slope-intercept form is:
\[
y = -3x - 13
\]
Next, we can check which of the points provided is on the graph of the line by substituting each point's coordinates into the equation \(y = -3x - 13\).
1. For \((5, 6)\):
\[
y = -3(5) - 13 = -15 - 13 = -28 \quad (\text{not on the line})
\]
2. For \((-5, -6)\):
\[
y = -3(-5) - 13 = 15 - 13 = 2 \quad (\text{not on the line})
\]
3. For \((6, 5)\):
\[
y = -3(6) - 13 = -18 - 13 = -31 \quad (\text{not on the line})
\]
4. For \((0, 0)\):
\[
y = -3(0) - 13 = 0 - 13 = -13 \quad (\text{not on the line})
\]
5. For \((-6, 5)\):
\[
y = -3(-6) - 13 = 18 - 13 = 5 \quad (\text{this point is on the line})
\]
Thus, the point on the graph of the line is \((-6, 5)\).
### Final Answers:
- The equation in slope-intercept form is: **\( y = -3x - 13 \)**
- The point on the graph of the line is: **\((-6, 5)\)**.
1. Distribute \(-3\) on the right side:
\[
y - 5 = -3x - 18
\]
2. Add \(5\) to both sides to isolate \(y\):
\[
y = -3x - 18 + 5
\]
3. Simplify the right side:
\[
y = -3x - 13
\]
So, the equation in slope-intercept form is:
\[
y = -3x - 13
\]
Next, we can check which of the points provided is on the graph of the line by substituting each point's coordinates into the equation \(y = -3x - 13\).
1. For \((5, 6)\):
\[
y = -3(5) - 13 = -15 - 13 = -28 \quad (\text{not on the line})
\]
2. For \((-5, -6)\):
\[
y = -3(-5) - 13 = 15 - 13 = 2 \quad (\text{not on the line})
\]
3. For \((6, 5)\):
\[
y = -3(6) - 13 = -18 - 13 = -31 \quad (\text{not on the line})
\]
4. For \((0, 0)\):
\[
y = -3(0) - 13 = 0 - 13 = -13 \quad (\text{not on the line})
\]
5. For \((-6, 5)\):
\[
y = -3(-6) - 13 = 18 - 13 = 5 \quad (\text{this point is on the line})
\]
Thus, the point on the graph of the line is \((-6, 5)\).
### Final Answers:
- The equation in slope-intercept form is: **\( y = -3x - 13 \)**
- The point on the graph of the line is: **\((-6, 5)\)**.
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