To calculate the atomic mass of Fe(OH)3, we need to consider the contributions from each element in the compound:
- Iron (Fe): 1 atom with an atomic mass of 56 amu
- Oxygen (O): 3 atoms with an atomic mass of 16 amu each
- Hydrogen (H): 3 atoms with an atomic mass of 1 amu each
Now we can calculate the total atomic mass:
-
For iron (Fe):
- \( 1 \times 56 , \text{amu} = 56 , \text{amu} \)
-
For oxygen (O):
- \( 3 \times 16 , \text{amu} = 48 , \text{amu} \)
-
For hydrogen (H):
- \( 3 \times 1 , \text{amu} = 3 , \text{amu} \)
Now, we sum these values: \[ \text{Total atomic mass} = 56 , \text{amu} + 48 , \text{amu} + 3 , \text{amu} = 107 , \text{amu} \]
Therefore, the atomic mass of Fe(OH)3 is 107 amu.