Question
Apply the Properties of Integer Exponents to generate equivalent expressions to
4^0 x 5^-2/ (-2)^-3
with positive exponents only, then solve the expression
4^0 x 5^-2/ (-2)^-3
with positive exponents only, then solve the expression
Answers
Answer
CHAT GPT. 0, dummy, you got it wrong
Answered by
GPT-4o mini
To simplify the expression \( \frac{4^0 \times 5^{-2}}{(-2)^{-3}} \) using the properties of integer exponents, we first rewrite each term with positive exponents.
1. **Calculate \(4^0\)**:
\[
4^0 = 1
\]
2. **Rewrite \(5^{-2}\)**:
\[
5^{-2} = \frac{1}{5^2} = \frac{1}{25}
\]
3. **Rewrite \((-2)^{-3}\)**:
\[
(-2)^{-3} = \frac{1}{(-2)^3} = \frac{1}{-8}
\]
Now, substitute these values back into the expression:
\[
\frac{4^0 \times 5^{-2}}{(-2)^{-3}} = \frac{1 \times \frac{1}{25}}{\frac{1}{-8}} = \frac{\frac{1}{25}}{\frac{1}{-8}}
\]
4. **Dividing fractions**: To divide by a fraction, multiply by its reciprocal:
\[
\frac{\frac{1}{25}}{\frac{1}{-8}} = \frac{1}{25} \times (-8) = -\frac{8}{25}
\]
Thus, the expression \( \frac{4^0 \times 5^{-2}}{(-2)^{-3}} \), simplified to have only positive exponents, results in:
\[
-\frac{8}{25}
\]
Final result:
\[
\boxed{-\frac{8}{25}}
\]
1. **Calculate \(4^0\)**:
\[
4^0 = 1
\]
2. **Rewrite \(5^{-2}\)**:
\[
5^{-2} = \frac{1}{5^2} = \frac{1}{25}
\]
3. **Rewrite \((-2)^{-3}\)**:
\[
(-2)^{-3} = \frac{1}{(-2)^3} = \frac{1}{-8}
\]
Now, substitute these values back into the expression:
\[
\frac{4^0 \times 5^{-2}}{(-2)^{-3}} = \frac{1 \times \frac{1}{25}}{\frac{1}{-8}} = \frac{\frac{1}{25}}{\frac{1}{-8}}
\]
4. **Dividing fractions**: To divide by a fraction, multiply by its reciprocal:
\[
\frac{\frac{1}{25}}{\frac{1}{-8}} = \frac{1}{25} \times (-8) = -\frac{8}{25}
\]
Thus, the expression \( \frac{4^0 \times 5^{-2}}{(-2)^{-3}} \), simplified to have only positive exponents, results in:
\[
-\frac{8}{25}
\]
Final result:
\[
\boxed{-\frac{8}{25}}
\]
Answered by
GPT-4o mini
Let’s go through the calculation again step by step to ensure accuracy.
We are given the expression:
\[
\frac{4^0 \times 5^{-2}}{(-2)^{-3}}
\]
### Step 1: Simplify \(4^0\)
\[
4^0 = 1
\]
### Step 2: Simplify \(5^{-2}\)
Using the property of negative exponents:
\[
5^{-2} = \frac{1}{5^2} = \frac{1}{25}
\]
### Step 3: Simplify \((-2)^{-3}\)
Using the property of negative exponents:
\[
(-2)^{-3} = \frac{1}{(-2)^3}
\]
Calculating \((-2)^3\):
\[
(-2)^3 = -8 \quad \text{so} \quad (-2)^{-3} = \frac{1}{-8}
\]
### Step 4: Substitute these values into the expression
Now substituting back into the original expression:
\[
\frac{4^0 \times 5^{-2}}{(-2)^{-3}} = \frac{1 \times \frac{1}{25}}{\frac{1}{-8}} = \frac{\frac{1}{25}}{\frac{1}{-8}}
\]
### Step 5: Dividing fractions
Dividing by a fraction means multiplying by its reciprocal:
\[
\frac{\frac{1}{25}}{\frac{1}{-8}} = \frac{1}{25} \times \left(-8\right) = -\frac{8}{25}
\]
### Final Result
The simplified expression, with all positive exponents, is:
\[
-\frac{8}{25}
\]
If any specific part of the process seems incorrect, please let me know! Otherwise, this confirms the evaluation of the expression as \( \boxed{-\frac{8}{25}} \).
We are given the expression:
\[
\frac{4^0 \times 5^{-2}}{(-2)^{-3}}
\]
### Step 1: Simplify \(4^0\)
\[
4^0 = 1
\]
### Step 2: Simplify \(5^{-2}\)
Using the property of negative exponents:
\[
5^{-2} = \frac{1}{5^2} = \frac{1}{25}
\]
### Step 3: Simplify \((-2)^{-3}\)
Using the property of negative exponents:
\[
(-2)^{-3} = \frac{1}{(-2)^3}
\]
Calculating \((-2)^3\):
\[
(-2)^3 = -8 \quad \text{so} \quad (-2)^{-3} = \frac{1}{-8}
\]
### Step 4: Substitute these values into the expression
Now substituting back into the original expression:
\[
\frac{4^0 \times 5^{-2}}{(-2)^{-3}} = \frac{1 \times \frac{1}{25}}{\frac{1}{-8}} = \frac{\frac{1}{25}}{\frac{1}{-8}}
\]
### Step 5: Dividing fractions
Dividing by a fraction means multiplying by its reciprocal:
\[
\frac{\frac{1}{25}}{\frac{1}{-8}} = \frac{1}{25} \times \left(-8\right) = -\frac{8}{25}
\]
### Final Result
The simplified expression, with all positive exponents, is:
\[
-\frac{8}{25}
\]
If any specific part of the process seems incorrect, please let me know! Otherwise, this confirms the evaluation of the expression as \( \boxed{-\frac{8}{25}} \).
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