To solve \( 3^{-2} \) by \( -4 \), we first need to express \( 3^{-2} \) without any negative exponent. By the Property of Negative Integer Exponents, we have:
\[ 3^{-2} = \frac{1}{3^2} \]
Now, we calculate \( 3^2 \):
\[ 3^2 = 9 \]
Thus, we can substitute this back into our expression:
\[ 3^{-2} = \frac{1}{9} \]
Now we need to multiply this result by \( -4 \):
\[ \frac{1}{9} \times -4 = -\frac{4}{9} \]
Thus, the final answer is:
\[ -\frac{4}{9} \]