Asked by hi √
Using rational approximations, what statement is true?
√12> π
√12<π
√ 16 > 4
√16 < 4
√12> π
√12<π
√ 16 > 4
√16 < 4
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To evaluate the statements using rational approximations, we first need to determine the values of each expression.
1. **Calculating √12:**
\[
\sqrt{12} \approx 3.464
\]
2. **Calculating π:**
Using the approximate value of π:
\[
\pi \approx 3.142
\]
Now let's compare:
- \(\sqrt{12} \approx 3.464\) and \(\pi \approx 3.142\), therefore:
\[
\sqrt{12} > \pi
\]
3. **Calculating √16:**
\[
\sqrt{16} = 4
\]
Now let's compare:
- \(\sqrt{16} = 4\), thus:
\[
\sqrt{16} = 4
\]
which means that both \( \sqrt{16} > 4 \) and \( \sqrt{16} < 4 \) are false.
Based on these calculations, the only true statement among the ones provided is:
\[
\sqrt{12} > \pi
\]
1. **Calculating √12:**
\[
\sqrt{12} \approx 3.464
\]
2. **Calculating π:**
Using the approximate value of π:
\[
\pi \approx 3.142
\]
Now let's compare:
- \(\sqrt{12} \approx 3.464\) and \(\pi \approx 3.142\), therefore:
\[
\sqrt{12} > \pi
\]
3. **Calculating √16:**
\[
\sqrt{16} = 4
\]
Now let's compare:
- \(\sqrt{16} = 4\), thus:
\[
\sqrt{16} = 4
\]
which means that both \( \sqrt{16} > 4 \) and \( \sqrt{16} < 4 \) are false.
Based on these calculations, the only true statement among the ones provided is:
\[
\sqrt{12} > \pi
\]
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