Question

2-Variable Equations & Inequalities Online Practice
Complete this assessment to review what you’ve learned. It will not count toward your grade.
4 of 184 of 18 Items






Question
To raise money, the student council at a local middle school is hosting a talent show. Tickets are sold for $5.00 for students (x) and $8.00 for adults (y). The goal is to raise a total of $1,575.00. Which of the following is a viable solution for the number of student and adult tickets that can be sold?(1 point)
Responses

(125,115)
left parenthesis 125 comma 115 right parenthesis

(371,−35)
left parenthesis negative 371 comma negative 35 right parenthesis

(115,125)
left parenthesis 115 comma 125 right parenthesis

(81,146.25)

Answer 1

To determine which option is a viable solution for the number of student (x) and adult (y) tickets sold, we first need to establish the equation based on the information given.

The total revenue from ticket sales can be represented by the equation:

\[ 5x + 8y = 1575 \]

where:
- \( x \) is the number of student tickets sold
- \( y \) is the number of adult tickets sold

Now, we can check which of the given responses satisfies this equation.

1. For (125, 115):
\[ 5(125) + 8(115) = 625 + 920 = 1545 \] (not a solution)

2. For (371, -35):
\[ 5(371) + 8(-35) = 1855 - 280 = 1575 \] (but negative tickets are not feasible, so not a solution)

3. For (115, 125):
\[ 5(115) + 8(125) = 575 + 1000 = 1575 \] (this is a viable solution)

4. For (81, 146.25):
\[ 5(81) + 8(146.25) = 405 + 1170 = 1575 \] (but fractional tickets are not feasible, so not a solution)

The only viable solution from the provided options is:

**(115, 125)**