Determine the domain and range for the inverse of f left parenthesis x right parenthesis equals start fraction 1 over 4 x end fraction plus 2.

(1 point)
Responses

domain: left parenthesis negative infinity comma 0 right parenthesis
range: left parenthesis 2 comma infinity right parenthesis
domain: Image with alt text: left parenthesis negative infinity comma 0 right parenthesis range: Image with alt text: left parenthesis 2 comma infinity right parenthesis

domain: left parenthesis negative infinity comma 2 right parenthesis union left parenthesis 2 comma infinity right parenthesis
range: left parenthesis negative infinity comma 0 right parenthesis union left parenthesis 0 comma infinity right parenthesis
domain: Image with alt text: left parenthesis negative infinity comma 2 right parenthesis union left parenthesis 2 comma infinity right parenthesis range: Image with alt text: left parenthesis negative infinity comma 0 right parenthesis union left parenthesis 0 comma infinity right parenthesis

domain: left parenthesis negative infinity comma 0 right parenthesis union left parenthesis 0 comma infinity right parenthesis
range: left parenthesis negative infinity comma 2 right parenthesis union left parenthesis 2 comma infinity right parenthesis
domain: Image with alt text: left parenthesis negative infinity comma 0 right parenthesis union left parenthesis 0 comma infinity right parenthesis range: Image with alt text: left parenthesis negative infinity comma 2 right parenthesis union left parenthesis 2 comma infinity right parenthesis

domain: left parenthesis 0 comma infinity right parenthesis
range: left parenthesis negative infinity comma 2 right parenthesis

1 answer

To find the domain and range of the inverse of the function f(x)=14x+2, we first need to identify the domain and range of the original function.

Step 1: Determine the domain of f(x)

The function f(x)=14x+2 is defined for all x except x=0, since division by zero is undefined. Thus, the domain of f(x) is:

Domain of f(x)=(,0)(0,)

Step 2: Determine the range of f(x)

Next, we need to find the range of f(x). As x approaches 0 from the left, f(x) approaches . As x approaches 0 from the right, f(x) approaches +. The function f(x)=14x+2 has horizontal asymptotes with behavior that shows f(x) never actually reaches the value 2. Therefore, the range of f(x) is:

Range of f(x)=(,2)(2,)

Step 3: Determine the domain and range of the inverse function f1(x)

The domain of the inverse function f1(x) is equal to the range of the original function f(x), and the range of the inverse function is equal to the domain of the original function:

  • Domain of f1(x) is (,2)(2,)
  • Range of f1(x) is (,0)(0,)

Conclusion

Thus, the final answer for the domain and range of the inverse function is:

  • Domain: (,2)(2,)
  • Range: (,0)(0,)

The response that matches this is:

domain: (,2)(2,) range: (,0)(0,)