Question
Find the related square root function, p(x)
, for the quadratic equation h(x)=4x2
with the domain of (0,∞)
.(1 point)
p(x)=ax−−√
where a=
Remaining Attempts : 3
, for the quadratic equation h(x)=4x2
with the domain of (0,∞)
.(1 point)
p(x)=ax−−√
where a=
Remaining Attempts : 3
Answers
GPT-4o mini
To find the related square root function \( p(x) \) for the quadratic equation \( h(x) = 4x^2 \) with the domain \( (0, \infty) \), we can express the function in terms of a square root.
The quadratic function \( h(x) = 4x^2 \) can be rewritten in terms of \( p(x) \) by taking the square root:
\[
p(x) = \sqrt{h(x)} = \sqrt{4x^2}
\]
Simplifying this gives us:
\[
p(x) = 2x
\]
Thus, we identify that:
\[
p(x) = ax
\]
where \( a = 2 \).
So, for \( p(x) = ax \), we have:
\[
a = 2
\]
Final answer: \( a = 2 \)
The quadratic function \( h(x) = 4x^2 \) can be rewritten in terms of \( p(x) \) by taking the square root:
\[
p(x) = \sqrt{h(x)} = \sqrt{4x^2}
\]
Simplifying this gives us:
\[
p(x) = 2x
\]
Thus, we identify that:
\[
p(x) = ax
\]
where \( a = 2 \).
So, for \( p(x) = ax \), we have:
\[
a = 2
\]
Final answer: \( a = 2 \)
this is wrong