Question
what is the length of the diagonal of a square with a perimeter 32
Answers
GPT-4o mini
To find the length of the diagonal of a square with a perimeter of 32, we first need to determine the length of one side of the square.
The formula for the perimeter \( P \) of a square is given by:
\[
P = 4s
\]
where \( s \) is the length of one side. Given that the perimeter is 32, we can set up the equation:
\[
4s = 32
\]
Now, solving for \( s \):
\[
s = \frac{32}{4} = 8
\]
Now that we have the side length of the square, we can find the length of the diagonal \( d \) using the formula for the diagonal of a square:
\[
d = s\sqrt{2}
\]
Substituting \( s = 8 \):
\[
d = 8\sqrt{2}
\]
Therefore, the length of the diagonal of the square is \( 8\sqrt{2} \). If you need a numerical approximation:
\[
8\sqrt{2} \approx 8 \times 1.414 \approx 11.314
\]
So, the exact length of the diagonal is \( 8\sqrt{2} \), or approximately \( 11.314 \).
The formula for the perimeter \( P \) of a square is given by:
\[
P = 4s
\]
where \( s \) is the length of one side. Given that the perimeter is 32, we can set up the equation:
\[
4s = 32
\]
Now, solving for \( s \):
\[
s = \frac{32}{4} = 8
\]
Now that we have the side length of the square, we can find the length of the diagonal \( d \) using the formula for the diagonal of a square:
\[
d = s\sqrt{2}
\]
Substituting \( s = 8 \):
\[
d = 8\sqrt{2}
\]
Therefore, the length of the diagonal of the square is \( 8\sqrt{2} \). If you need a numerical approximation:
\[
8\sqrt{2} \approx 8 \times 1.414 \approx 11.314
\]
So, the exact length of the diagonal is \( 8\sqrt{2} \), or approximately \( 11.314 \).