Question
Evaluate the expression Sa = bc^3 when a = -2, b = 1/3, and c = 3
Answers
Answer
include a = -2
Answered by
GPT-4o mini
To evaluate the expression \( S_a = b c^3 \) with the given values \( a = -2 \), \( b = \frac{1}{3} \), and \( c = 3 \), we will first substitute the value of \( b \) and \( c \) into the expression:
1. Substitute \( c = 3 \) into \( c^3 \):
\[
c^3 = 3^3 = 27
\]
2. Now substitute \( b \) and the calculated \( c^3 \) into the expression:
\[
S_a = b c^3 = \frac{1}{3} \cdot 27
\]
3. Multiply \( \frac{1}{3} \) by \( 27 \):
\[
S_a = \frac{27}{3} = 9
\]
Thus, the value of the expression \( S_a \) is \( \boxed{9} \).
1. Substitute \( c = 3 \) into \( c^3 \):
\[
c^3 = 3^3 = 27
\]
2. Now substitute \( b \) and the calculated \( c^3 \) into the expression:
\[
S_a = b c^3 = \frac{1}{3} \cdot 27
\]
3. Multiply \( \frac{1}{3} \) by \( 27 \):
\[
S_a = \frac{27}{3} = 9
\]
Thus, the value of the expression \( S_a \) is \( \boxed{9} \).
Answered by
GPT-4o mini
It appears that the variable \( a \) isn't used in the expression \( S_a = b c^3 \). However, if you would like to see it included in the context or if there are additional calculations or usages for \( a \), please clarify.
Nonetheless, I can reaffirm the evaluation of \( S_a = b c^3 \) with respect to the provided values:
Given:
- \( a = -2 \) (not used in the current expression)
- \( b = \frac{1}{3} \)
- \( c = 3 \)
Let’s summarize the calculation again:
1. Calculate \( c^3 \):
\[
c^3 = 3^3 = 27
\]
2. Substitute \( b \) and \( c^3 \) into the expression:
\[
S_a = b c^3 = \frac{1}{3} \cdot 27
\]
3. Perform the multiplication:
\[
S_a = \frac{27}{3} = 9
\]
So, even though \( a \) is given as \( -2 \), it does not affect the calculation of \( S_a = b c^3 \). Therefore, the final result remains \( \boxed{9} \).
If there's a specific way in which you would like \( a \) to be used in relation to \( S_a \), please let me know!
Nonetheless, I can reaffirm the evaluation of \( S_a = b c^3 \) with respect to the provided values:
Given:
- \( a = -2 \) (not used in the current expression)
- \( b = \frac{1}{3} \)
- \( c = 3 \)
Let’s summarize the calculation again:
1. Calculate \( c^3 \):
\[
c^3 = 3^3 = 27
\]
2. Substitute \( b \) and \( c^3 \) into the expression:
\[
S_a = b c^3 = \frac{1}{3} \cdot 27
\]
3. Perform the multiplication:
\[
S_a = \frac{27}{3} = 9
\]
So, even though \( a \) is given as \( -2 \), it does not affect the calculation of \( S_a = b c^3 \). Therefore, the final result remains \( \boxed{9} \).
If there's a specific way in which you would like \( a \) to be used in relation to \( S_a \), please let me know!
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