Question
What is the wavelength of waves that have a frequency of 2.20 x 10−4 Hz?
7.30 x 10−13 m
6.60 x 104 m
5.50 x 108 m
1.36 x 1012 m
7.30 x 10−13 m
6.60 x 104 m
5.50 x 108 m
1.36 x 1012 m
Answers
Answered by
GPT-4o mini
To calculate the wavelength (\( \lambda \)) of a wave, you can use the formula:
\[
\lambda = \frac{v}{f}
\]
where \( v \) is the speed of the wave and \( f \) is the frequency. For electromagnetic waves in a vacuum, the speed \( v \) is approximately \( 3.00 \times 10^8 \) m/s (the speed of light).
Given the frequency \( f = 2.20 \times 10^{-4} \) Hz, we can substitute into the formula:
\[
\lambda = \frac{3.00 \times 10^8 \, \text{m/s}}{2.20 \times 10^{-4} \, \text{Hz}}
\]
Now, calculating \( \lambda \):
\[
\lambda = \frac{3.00 \times 10^8}{2.20 \times 10^{-4}} \approx 1.36 \times 10^{12} \, \text{m}
\]
So the wavelength of the waves is approximately \( 1.36 \times 10^{12} \) m.
From the options provided:
- 7.30 x 10−13 m
- 6.60 x 10^4 m
- 5.50 x 10^8 m
- **1.36 x 10^12 m**
The correct answer is **1.36 x 10^12 m**.
\[
\lambda = \frac{v}{f}
\]
where \( v \) is the speed of the wave and \( f \) is the frequency. For electromagnetic waves in a vacuum, the speed \( v \) is approximately \( 3.00 \times 10^8 \) m/s (the speed of light).
Given the frequency \( f = 2.20 \times 10^{-4} \) Hz, we can substitute into the formula:
\[
\lambda = \frac{3.00 \times 10^8 \, \text{m/s}}{2.20 \times 10^{-4} \, \text{Hz}}
\]
Now, calculating \( \lambda \):
\[
\lambda = \frac{3.00 \times 10^8}{2.20 \times 10^{-4}} \approx 1.36 \times 10^{12} \, \text{m}
\]
So the wavelength of the waves is approximately \( 1.36 \times 10^{12} \) m.
From the options provided:
- 7.30 x 10−13 m
- 6.60 x 10^4 m
- 5.50 x 10^8 m
- **1.36 x 10^12 m**
The correct answer is **1.36 x 10^12 m**.