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Use the Distributive Property to prove that these algebraic expressions are equivalent. Explain your answer in one sentence for...Question
Use the Distributive Property to prove that these algebraic expressions are equivalent. Explain your answer in one sentence for each expression and show your work.
Expression 1: (x−5)(x+3)
Expression 2: 2x2−x2−2x−20+5
(4 points)
Expression 1: (x−5)(x+3)
Expression 2: 2x2−x2−2x−20+5
(4 points)
Answers
could you say it more simply
Answered by
GPT-4o mini
To prove that the two expressions are equivalent using the Distributive Property, we'll expand Expression 1 and simplify Expression 2.
### Work for Expression 1:
1. **Expand (x−5)(x+3)** using the Distributive Property:
\[
(x - 5)(x + 3) = x(x + 3) - 5(x + 3)
\]
\[
= x^2 + 3x - 5x - 15
\]
\[
= x^2 - 2x - 15
\]
### Work for Expression 2:
2. **Simplify the Expression 2:**
\[
2x^2 - x^2 - 2x - 20 + 5
\]
- Combine like terms:
\[
= (2x^2 - x^2) - 2x - 20 + 5
\]
\[
= x^2 - 2x - 15
\]
### Conclusion:
Both expressions simplify to \(x^2 - 2x - 15\), therefore proving they are equivalent.
- Expression 1, when expanded, gives \(x^2 - 2x - 15\), and Expression 2 simplifies to the same form \(x^2 - 2x - 15\), confirming their equivalence.
### Work for Expression 1:
1. **Expand (x−5)(x+3)** using the Distributive Property:
\[
(x - 5)(x + 3) = x(x + 3) - 5(x + 3)
\]
\[
= x^2 + 3x - 5x - 15
\]
\[
= x^2 - 2x - 15
\]
### Work for Expression 2:
2. **Simplify the Expression 2:**
\[
2x^2 - x^2 - 2x - 20 + 5
\]
- Combine like terms:
\[
= (2x^2 - x^2) - 2x - 20 + 5
\]
\[
= x^2 - 2x - 15
\]
### Conclusion:
Both expressions simplify to \(x^2 - 2x - 15\), therefore proving they are equivalent.
- Expression 1, when expanded, gives \(x^2 - 2x - 15\), and Expression 2 simplifies to the same form \(x^2 - 2x - 15\), confirming their equivalence.
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