Asked by larry
i am having a minor difficulty
i've been stuck for over an hour and don't know what to do
i don't know is this right
? = "+" or "-"
# = number
y=x
(x+1)squared + (y+1)squared = 6
i substitute y
(x+1)squared + (x+1)squared = 6
x squared + 2x + 1 + x squared + 2x + 1 = 6
2x squared + 4x + 2 = 6
2x squared + 4x - 4 = 0
2(x squared + 2x - 2) = 0
2(x ? #)(x ? #)
i get to here and now i am stuck
can u correct me if i did something wrong
please and thank you
i've been stuck for over an hour and don't know what to do
i don't know is this right
? = "+" or "-"
# = number
y=x
(x+1)squared + (y+1)squared = 6
i substitute y
(x+1)squared + (x+1)squared = 6
x squared + 2x + 1 + x squared + 2x + 1 = 6
2x squared + 4x + 2 = 6
2x squared + 4x - 4 = 0
2(x squared + 2x - 2) = 0
2(x ? #)(x ? #)
i get to here and now i am stuck
can u correct me if i did something wrong
please and thank you
Answers
Answered by
Reiny
You did nothing wrong, but not every quadratic factors.
An easier way is not to expand it.
from
(x+1)^2 + (x+1)^2 = 6
2(x+)^2 = 6
(x+1)^2 = 3
x+1 = ± √3
x = -1 ± √3
take it from here
An easier way is not to expand it.
from
(x+1)^2 + (x+1)^2 = 6
2(x+)^2 = 6
(x+1)^2 = 3
x+1 = ± √3
x = -1 ± √3
take it from here
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