1 answer
(click or scroll down)
To solve the equation \( 2x^{32} = 16 \), we can first express 16 in terms of a power of 2:
\[
16 = 2^4
\]
This allows us to rewrite the equation as:
\[
2x^{32} = 2^4
\]
Now, we can divide both sides by 2 (assuming \( x^{32} \neq 0 \)):
\[
x^{32} = 2^3
\]
This simplifies to:
\[
x^{32} = 8
\]
Now, to solve for \( x \), we take the 32nd root of both sides:
\[
x = 8^{\frac{1}{32}}
\]
Next, since \( 8 = 2^3 \), we can rewrite this as:
\[
x = (2^3)^{\frac{1}{32}} = 2^{\frac{3}{32}}
\]
Thus, the solution can be expressed as:
\[
x = 2^{\frac{3}{32}}
\]
This result does not match any of the given responses exactly, implying that there is no solution among the provided options.
Therefore, the correct response is:
**no solution**