To determine which ordered pair is a solution to the equation \( 8 - 2y = 4x^2 \), we will substitute each pair \((x, y)\) into the equation and check if the equation holds true.
Check Option #1: \((0, 8)\)
Substituting \(x = 0\) and \(y = 8\) into the equation: \[ 8 - 2(8) = 4(0^2) \] \[ 8 - 16 = 0 \] \[ -8 = 0 \quad \text{(False)} \]
Check Option #2: \((-1, 2)\)
Substituting \(x = -1\) and \(y = 2\) into the equation: \[ 8 - 2(2) = 4(-1^2) \] \[ 8 - 4 = 4(1) \] \[ 4 = 4 \quad \text{(True)} \]
Check Option #3: \((4, 0)\)
Substituting \(x = 4\) and \(y = 0\) into the equation: \[ 8 - 2(0) = 4(4^2) \] \[ 8 = 4(16) \] \[ 8 = 64 \quad \text{(False)} \]
The only ordered pair that is a solution to the equation is Option #2: (-1, 2).
So, Option #2 is a solution to the equation.
1 answer