Question

Which one of the following correctly divides 18xsquaredplus 9x + 3 / -3x

Answer 1

To divide the expression \( 18x^2 + 9x + 3 \) by \(-3x\), you can perform the operation for each term in the polynomial.

1. Start with the expression:

\[
\frac{18x^2 + 9x + 3}{-3x}
\]

2. Divide each term in the numerator by \(-3x\):
- For the first term:

\[
\frac{18x^2}{-3x} = -6x
\]

- For the second term:

\[
\frac{9x}{-3x} = -3
\]

- For the third term:

\[
\frac{3}{-3x} = -\frac{1}{x}
\]

3. Combine the results:

\[
-6x - 3 - \frac{1}{x}
\]

Thus, the result of dividing \( 18x^2 + 9x + 3 \) by \(-3x\) is:

\[
-6x - 3 - \frac{1}{x}
\]