Question

Which one of the following correctly divides 18x plus 9x + 3 / -3x

Answer 1

To divide the expression \(18x + 9x + 3\) by \(-3x\), we first simplify the numerator.

1. Combine like terms in the numerator:
\[
18x + 9x + 3 = 27x + 3
\]

Now we have:
\[
\frac{27x + 3}{-3x}
\]

2. Factor out the common factor in the numerator:
\[
27x + 3 = 3(9x + 1)
\]

So the expression now looks like:
\[
\frac{3(9x + 1)}{-3x}
\]

3. Simplify the fraction:
\[
\frac{3(9x + 1)}{-3x} = \frac{3}{-3} \cdot \frac{9x + 1}{x} = -1 \cdot \frac{9x + 1}{x}
\]

4. Therefore, we can express the final result as:
\[
-\frac{9x + 1}{x}
\]
Or split into two parts:
\[
-9 - \frac{1}{x}
\]

So the final result for the division of \(18x + 9x + 3\) by \(-3x\) is:
\[
-\frac{9x + 1}{x}
\]