To find the length of \( TV \) in triangle \( RST \), we can apply the Pythagorean theorem.
Given:
- \( SV = 12 \) (length of segment \( SV \))
- \( VR = 30 \) (length of segment \( VR \))
Since \( SV \) and \( VR \) are both segments forming right angles with the sides of triangle \( RST \) and because the right angle is at \( S \), we can view this as two right triangles, \( SVR \) and \( SVT \), where \( SV \) is a common side.
To find \( RV \):
Using the Pythagorean theorem in triangle \( SVR \):
\[ SV^2 + VR^2 = SR^2 \]
Substituting the known lengths:
\[ 12^2 + 30^2 = SR^2 \] \[ 144 + 900 = SR^2 \] \[ SR^2 = 1044 \] \[ SR = \sqrt{1044} \approx 32.31 \]
Next, in triangle \( SVT \), we apply the Pythagorean theorem again. We are trying to find \( TV \):
\[ SV^2 + ST^2 = VT^2 \]
Since we already have \( SV \) and \( SR \):
Using the Pythagorean theorem in triangle \( RST \):
\[ RT^2 = RS^2 + ST^2 \]
We need to find \( RT \) or \( TV \). \( RT \) is the hypotenuse which we will denote as more.
Instead of going through \( SR \), we can rearrange the previous formulations using the hypotenuse defined by \( T \) to find \( TV \):
( RV^2 + SV^2 = TV^2 )
Using the two segments we already have:
( 30^2 + 12^2 = TV^2 )
Calculating:
\[ 900 + 144 = TV^2 \] \[ TV^2 = 1044 \] \[ TV = \sqrt{1044} = 32.31 \]
So, the length of \( TV \) is approximately:
\( 32.31 \)
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