Asked by Elijah Hewson
which of the following is the simplified form of (-10x^2 +20x+80)/(x+2)
Answers
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Answered by
GPT-4o mini
To simplify the expression \((-10x^2 + 20x + 80)/(x + 2)\), we can use polynomial long division or synthetic division.
Let's perform polynomial long division:
1. Divide the leading term of the numerator \(-10x^2\) by the leading term of the denominator \(x\) to get \(-10x\).
2. Multiply \(-10x\) by the entire divisor \((x + 2)\):
\[
-10x(x + 2) = -10x^2 - 20x
\]
3. Subtract this result from the original numerator:
\[
(-10x^2 + 20x + 80) - (-10x^2 - 20x) = 20x + 20x + 80 = 40x + 80
\]
4. Now, divide the leading term of the new polynomial \(40x + 80\) by the leading term of the denominator \(x\):
\[
\frac{40x}{x} = 40
\]
5. Multiply the entire divisor by \(40\):
\[
40(x + 2) = 40x + 80
\]
6. Subtract this from the remaining polynomial:
\[
(40x + 80) - (40x + 80) = 0
\]
The polynomial long division gives us:
\[
-10x + 40
\]
Since there is no remainder, the simplified form of \((-10x^2 + 20x + 80)/(x + 2)\) is:
\[
\boxed{-10x + 40}
\]
Let's perform polynomial long division:
1. Divide the leading term of the numerator \(-10x^2\) by the leading term of the denominator \(x\) to get \(-10x\).
2. Multiply \(-10x\) by the entire divisor \((x + 2)\):
\[
-10x(x + 2) = -10x^2 - 20x
\]
3. Subtract this result from the original numerator:
\[
(-10x^2 + 20x + 80) - (-10x^2 - 20x) = 20x + 20x + 80 = 40x + 80
\]
4. Now, divide the leading term of the new polynomial \(40x + 80\) by the leading term of the denominator \(x\):
\[
\frac{40x}{x} = 40
\]
5. Multiply the entire divisor by \(40\):
\[
40(x + 2) = 40x + 80
\]
6. Subtract this from the remaining polynomial:
\[
(40x + 80) - (40x + 80) = 0
\]
The polynomial long division gives us:
\[
-10x + 40
\]
Since there is no remainder, the simplified form of \((-10x^2 + 20x + 80)/(x + 2)\) is:
\[
\boxed{-10x + 40}
\]
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