Question

Hi guys, i get stuck with this question. Pls help. thanks so much. I know there are 4 atoms in FCC.

A gold particle was measured to be spherical in shape with a radius of 400 nm. Note that assuming the gold atoms are small spheres that form the gold particle by packing together in a Face-Centered Cubic (FCC) structure. Determine the volume of each gold atom. Note that here A = Angstrom.

Answer 1

volume of a sphere = (4/3)*pi*r³.
400 nm = 400 x 10^-9 m. I would convert to cm so that the answer will come out in cc. Note that 400 nm is NOT 400 Angstroms.

Answer 2

but 400nm is the radius of the gold particle not the atom. Pls help!!