Question
Use the substitution method to solve the system 2x+3y=4, −4x−6y=−8.(1 point)%0D%0AResponses%0D%0A%0D%0Ano solution%0D%0Ano solution%0D%0A%0D%0A(2−1)%0D%0Aleft parenthesis 2 comma negative 1 right parenthesis%0D%0A%0D%0Ainfinite solutions%0D%0Ainfinite solutions%0D%0A%0D%0A(−1,2)
Answers
Answered by
GPT-4o mini
To solve the system of equations using the substitution method, we start with the two equations:
1. \( 2x + 3y = 4 \)
2. \( -4x - 6y = -8 \)
First, let's solve Equation 1 for one variable, say \( y \):
\[
2x + 3y = 4
\]
Subtract \( 2x \) from both sides:
\[
3y = 4 - 2x
\]
Now, divide by 3:
\[
y = \frac{4 - 2x}{3}
\]
Next, we'll substitute this expression for \( y \) into Equation 2:
\[
-4x - 6y = -8
\]
Substituting \( y \) gives:
\[
-4x - 6\left(\frac{4 - 2x}{3}\right) = -8
\]
Multiply through by 3 to eliminate the fraction:
\[
-12x - 6(4 - 2x) = -24
\]
Distributing \( -6 \):
\[
-12x - 24 + 12x = -24
\]
Now, notice that the \( -12x \) and \( 12x \) cancel out:
\[
-24 = -24
\]
This is a true statement, indicating that the two equations are actually equivalent and therefore give us the same line. Thus, the system has **infinite solutions**.
The final answer is **infinite solutions**.
1. \( 2x + 3y = 4 \)
2. \( -4x - 6y = -8 \)
First, let's solve Equation 1 for one variable, say \( y \):
\[
2x + 3y = 4
\]
Subtract \( 2x \) from both sides:
\[
3y = 4 - 2x
\]
Now, divide by 3:
\[
y = \frac{4 - 2x}{3}
\]
Next, we'll substitute this expression for \( y \) into Equation 2:
\[
-4x - 6y = -8
\]
Substituting \( y \) gives:
\[
-4x - 6\left(\frac{4 - 2x}{3}\right) = -8
\]
Multiply through by 3 to eliminate the fraction:
\[
-12x - 6(4 - 2x) = -24
\]
Distributing \( -6 \):
\[
-12x - 24 + 12x = -24
\]
Now, notice that the \( -12x \) and \( 12x \) cancel out:
\[
-24 = -24
\]
This is a true statement, indicating that the two equations are actually equivalent and therefore give us the same line. Thus, the system has **infinite solutions**.
The final answer is **infinite solutions**.
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