To determine which equation creates a true equivalent system with the given systems, we need to see if any of the options are equivalent to the original equations in system A or system B.
The equations in System A are:
- \(-x + y = 1\)
- \(x + y = 11\)
The second equation \(x + y = 11\) is also given in System B.
Next, let's check each option to see if it maintains the same solutions as the above equations:
-
Option: \(-2x - 2y = -22\)
- Dividing by -2 gives: \(x + y = 11\) (which is equivalent to one of our equations).
-
Option: \(2y = 12\)
- Dividing the whole equation by 2 gives: \(y = 6\). This is not equivalent to any of the original equations.
-
Option: \(-x - y = -1\)
- Rearranging gives: \(x + y = 1\) (which is not equivalent to any of the original equations).
-
Option: \(2x + 2y = 12\)
- Dividing by 2 gives: \(x + y = 6\) (which is not equivalent to any of the original equations).
The only option that is equivalent to the original equations is:
Option: (-2x - 2y = -22
So the correct answer is:
\(-2x - 2y = -22\)