To solve for \(6^{-2}\), we can use the property of negative exponents, which states that \(a^{-n} = \frac{1}{a^n}\).
Thus, we have:
\[ 6^{-2} = \frac{1}{6^2} = \frac{1}{36} \]
Therefore, the equivalent expression for \(6^{-2}\) is:
\[ \frac{1}{36} \]
So the correct response is:
Start Fraction 1 over 36 End Fraction