To determine if the point (3,8) is a solution to the simultaneous inequalities \(y > x + 5\) and \(y \leq 6x - 3\), we can substitute \(x = 3\) and \(y = 8\) into each inequality.
1. **Testing the first inequality \(y > x + 5\):**
\[
8 > 3 + 5
\]
\[
8 > 8 \quad (\text{This is false.})
\]
2. **Testing the second inequality \(y \leq 6x - 3\):**
\[
8 \leq 6(3) - 3
\]
\[
8 \leq 18 - 3
\]
\[
8 \leq 15 \quad (\text{This is true.})
\]
Since the point (3, 8) does not satisfy the first inequality (it is not greater than \(x + 5\)), but it does satisfy the second inequality (it is less than or equal to \(6x - 3\)), the correct answer is:
**No, it is in the solution set for \(y \leq 6x - 3\), but on the line for \(y > x + 5\).**