To determine if the point (3,8) is a solution to the simultaneous inequalities \(y > x + 5\) and \(y \leq 6x - 3\), we can substitute \(x = 3\) and \(y = 8\) into each inequality.
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Testing the first inequality \(y > x + 5\): \[ 8 > 3 + 5 \] \[ 8 > 8 \quad (\text{This is false.}) \]
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Testing the second inequality \(y \leq 6x - 3\): \[ 8 \leq 6(3) - 3 \] \[ 8 \leq 18 - 3 \] \[ 8 \leq 15 \quad (\text{This is true.}) \]
Since the point (3, 8) does not satisfy the first inequality (it is not greater than \(x + 5\)), but it does satisfy the second inequality (it is less than or equal to \(6x - 3\)), the correct answer is:
No, it is in the solution set for \(y \leq 6x - 3\), but on the line for \(y > x + 5\).