To solve the system of equations using the substitution method, we have the following equations:
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\( 9x - 3y = 12 \)
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\( y + 6 = 2x \)
Let's start with Equation 2 to express \( y \) in terms of \( x \):
\[ y + 6 = 2x \]
Now, isolate \( y \):
\[ y = 2x - 6 \]
Next, we will substitute this expression for \( y \) into Equation 1:
\[ 9x - 3(2x - 6) = 12 \]
Now, distribute the \(-3\):
\[ 9x - 6x + 18 = 12 \]
Combine like terms:
\[ 3x + 18 = 12 \]
Now, isolate \( x \) by subtracting 18 from both sides:
\[ 3x = 12 - 18 \] \[ 3x = -6 \]
Now divide by 3:
\[ x = -2 \]
Next, substitute \( x = -2 \) back into the expression for \( y \):
\[ y = 2(-2) - 6 \] \[ y = -4 - 6 \] \[ y = -10 \]
Thus, the solution to the system of equations is:
\[ (x, y) = (-2, -10) \]
The final answer is \((-2, -10)\).