2f/5 - 8/5 + 2f=8

Answer 1

To solve the equation $\frac{2f}{5}-\frac{8}{5}+2f=8$, follow these steps:

1. Combine the terms involving $f$. $$\frac{2f}{5}+2f=\frac{2f}{5}+\frac{10f}{5}=\frac{12f}{5}$$ Therefore, the equation becomes: $$\frac{12f}{5}-\frac{8}{5}=8$$

2. Add $\frac{8}{5}$ to both sides to isolate the term with $f$: $$\frac{12f}{5}=8+\frac{8}{5}$$

3. Convert $8$ to a fraction with a denominator of 5: $$8=\frac{40}{5}$$ So, $$\frac{12f}{5}=\frac{40}{5}+\frac{8}{5}=\frac{48}{5}$$

4. Now, multiply both sides by 5 to eliminate the fraction: $$12f=48$$

5. Divide by 12 to solve for $f$: $$f=\frac{48}{12}=4$$

Thus, the solution is: $$\boxed{{\displaystyle 4}}$$