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What is the product of the polynomials (x^2y+2)(x^2−y)?(1 point) Responses x3y−x2y2+2x2−2y x cubed y minus x squared y squared...Question
What is the product of the polynomials (x2y+2)(x2−y)?(1 point)
Responses
x3y−x2y2+2x2−2y
x cubed y minus x squared y squared plus 2 x squared minus 2 y
x4y−x2y2+2x2−2y
x superscript 4 baseline y minus x squared y squared plus 2 x squared minus 2 y
x4y−xy+x2y
x superscript 4 baseline y minus x y plus x squared y
x4y+x2−2y
x superscript 4 baseline y plus x squared minus 2 y
Responses
x3y−x2y2+2x2−2y
x cubed y minus x squared y squared plus 2 x squared minus 2 y
x4y−x2y2+2x2−2y
x superscript 4 baseline y minus x squared y squared plus 2 x squared minus 2 y
x4y−xy+x2y
x superscript 4 baseline y minus x y plus x squared y
x4y+x2−2y
x superscript 4 baseline y plus x squared minus 2 y
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the product of the polynomials \((x^2y + 2)(x^2 - y)\), we can use the distributive property (also known as the FOIL method for binomials).
1. Distribute \(x^2y\) across \(x^2 - y\):
\[
x^2y \cdot x^2 + x^2y \cdot (-y) = x^4y - x^2y^2
\]
2. Distribute \(2\) across \(x^2 - y\):
\[
2 \cdot x^2 + 2 \cdot (-y) = 2x^2 - 2y
\]
Now, combine all the terms from both distributions:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
So, the final result is:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
Looking through the provided responses, the one that matches this result is:
\[
\text{x}^4\text{y} - \text{x}^2\text{y}^2 + 2\text{x}^2 - 2\text{y}
\]
Thus, the correct answer is:
\[
\text{x}^4\text{y} - \text{x}^2\text{y}^2 + 2\text{x}^2 - 2\text{y}
\]
1. Distribute \(x^2y\) across \(x^2 - y\):
\[
x^2y \cdot x^2 + x^2y \cdot (-y) = x^4y - x^2y^2
\]
2. Distribute \(2\) across \(x^2 - y\):
\[
2 \cdot x^2 + 2 \cdot (-y) = 2x^2 - 2y
\]
Now, combine all the terms from both distributions:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
So, the final result is:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
Looking through the provided responses, the one that matches this result is:
\[
\text{x}^4\text{y} - \text{x}^2\text{y}^2 + 2\text{x}^2 - 2\text{y}
\]
Thus, the correct answer is:
\[
\text{x}^4\text{y} - \text{x}^2\text{y}^2 + 2\text{x}^2 - 2\text{y}
\]
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