A pattern calls for three different fabrics.

To determine the order of the fabrics from least to greatest based on yards needed, we first need to convert all the measurements to a common format (decimals, which are easier to compare).

1. **Fabric A: 3 7/8 yards**
- Convert \( 7/8 \) to decimal: \( 7/8 = 0.875 \)
- So, \( 3 7/8 = 3 + 0.875 = 3.875 \) yards

2. **Fabric B: 3 1/5 yards**
- Convert \( 1/5 \) to decimal: \( 1/5 = 0.2 \)
- So, \( 3 1/5 = 3 + 0.2 = 3.2 \) yards

3. **Fabric C: 9/3 yards**
- Convert \( 9/3 = 3 \) yards

Now, we compare the three values:
- Fabric A: 3.875 yards
- Fabric B: 3.2 yards
- Fabric C: 3 yards

Ordering these from least to greatest:
1. Fabric C: 3 yards
2. Fabric B: 3.2 yards
3. Fabric A: 3.875 yards

So, the correct order from least to greatest is:

**C, B,

Therefore, the answer is **C, B, .

are you sure

Let's double-check the calculations and ensure the fabrics are arranged correctly from least to greatest:

1. **Fabric A: 3 7/8 yards**
- To convert \( 7/8 \) to a decimal, we have \( 7 \div 8 = 0.875 \).
- Therefore, \( 3 \frac{7}{8} = 3 + 0.875 = 3.875 \) yards.

2. **Fabric B: 3 1/5 yards**
- To convert \( 1/5 \) to a decimal, we have \( 1 \div 5 = 0.2 \).
- Therefore, \( 3 \frac{1}{5} = 3 + 0.2 = 3.2 \) yards.

3. **Fabric C: 9/3 yards**
- This simplifies to \( 3 \) yards (since \( 9 \div 3 = 3 \)).

Now we can compare the values directly:
- Fabric A: **3.875 yards**
- Fabric B: **3.2 yards**
- Fabric C: **3 yards**

Arranging these from least to greatest:
1. Fabric C: **3 yards**
2. Fabric B: **3.2 yards**
3. Fabric A: **3.875 yards**

The correct order is indeed **C, B, .

So, I can confirm that the original answer is correct: the fabrics should be listed in the order **C, B, from least to greatest. Thank you for your patience!

A bus left with 48 passengers. At the first stop, (1)/(8) of the total number of passengers fell. At the second stop, a certain number of passengers boarded, equal to (1)/(3) of those the bus was carrying at that moment. At the third stop (4)/(7) of the passengers I was carrying got off. At the fourth stop, half got off, and at the fifth, (3)/(4) of the people he was carrying got off. With how many passengers did the truck arrive at the sixth and final stop?

Let's go through each stop step-by-step, starting with the initial number of passengers.

### Initial Number of Passengers:
- Starting with **48 passengers**.

### First Stop:
- At the first stop, \(\frac{1}{8}\) of the total passengers fell off:
\[
\text{Passengers that fell off} = \frac{1}{8} \times 48 = 6
\]
- Remaining passengers:
\[
48 - 6 = 42
\]

### Second Stop:
- At the second stop, \(\frac{1}{3}\) of the current passengers boarded:
\[
\text{Passengers that boarded} = \frac{1}{3} \times 42 = 14
\]
- New total passengers:
\[
42 + 14 = 56
\]

### Third Stop:
- At the third stop, \(\frac{4}{7}\) of the passengers got off:
\[
\text{Passengers that got off} = \frac{4}{7} \times 56 = 32
\]
- Remaining passengers:
\[
56 - 32 = 24
\]

### Fourth Stop:
- At the fourth stop, half of the remaining passengers got off:
\[
\text{Passengers that got off} = \frac{1}{2} \times 24 = 12
\]
- Remaining passengers:
\[
24 - 12 = 12
\]

### Fifth Stop:
- At the fifth stop, \(\frac{3}{4}\) of the remaining passengers got off:
\[
\text{Passengers that got off} = \frac{3}{4} \times 12 = 9
\]
- Remaining passengers:
\[
12 - 9 = 3
\]

### Final Count:
- After all the stops, the bus arrived at the sixth and final stop with **3 passengers**.

Therefore, the bus arrived at the sixth and final stop with **3 passengers**.