To determine which of the given points is part of the solution set for the inequality \( y \leq 25x + 1 \), we will substitute the x and y coordinates of each point into the inequality and check if it holds true.
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For the point \( (-10, 6) \): \[ y \leq 25x + 1 \implies 6 \leq 25(-10) + 1 \implies 6 \leq -250 + 1 \implies 6 \leq -249 \quad \text{(False)} \]
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For the point \( (10, 5.5) \): \[ y \leq 25x + 1 \implies 5.5 \leq 25(10) + 1 \implies 5.5 \leq 250 + 1 \implies 5.5 \leq 251 \quad \text{(True)} \]
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For the point \( (10, 6) \): \[ y \leq 25x + 1 \implies 6 \leq 25(10) + 1 \implies 6 \leq 250 + 1 \implies 6 \leq 251 \quad \text{(True)} \]
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For the point \( (10, 4) \): \[ y \leq 25x + 1 \implies 4 \leq 25(10) + 1 \implies 4 \leq 250 + 1 \implies 4 \leq 251 \quad \text{(True)} \]
Thus, the points \( (10, 5.5) \), \( (10, 6) \), and \( (10, 4) \) are all part of the solution set for the inequality, while \( (-10, 6) \) is not.
Therefore, the points that are part of the solution set are:
- \( (10, 5.5) \)
- \( (10, 6) \)
- \( (10, 4) \)