The air temperature at 9 am is -5.8 degrees Celsius. The air temperature at noon is -1.6 degrees Celsius. What is the change in the temperature during these three hours? Write and solve an equation to show your answer. Then explain what your answer means

1 answer

To find the change in temperature from 9 am to noon, we can use the following equation:

\[ \text{Change in Temperature} = \text{Temperature at Noon} - \text{Temperature at 9 am} \]

Substituting the given values:

\[ \text{Change in Temperature} = -1.6 , \text{degrees Celsius} - (-5.8 , \text{degrees Celsius}) \]

This can be simplified as:

\[ \text{Change in Temperature} = -1.6 + 5.8 \]

Now calculate:

\[ -1.6 + 5.8 = 4.2 , \text{degrees Celsius} \]

So, the change in temperature is \( 4.2 , \text{degrees Celsius} \).

Explanation:

The result of \( 4.2 , \text{degrees Celsius} \) indicates that the air temperature increased by \( 4.2 \) degrees Celsius between 9 am and noon. This means that from a chilly morning of \( -5.8 \) degrees Celsius, the temperature rose to \( -1.6 \) degrees Celsius, marking a notable warm-up over the three-hour period.