The difference of the same side interior angles of 2 parallel lines is 50 degrees. Find the angles

1 answer

When two parallel lines are crossed by a transversal, the same side interior angles are supplementary, meaning they add up to 180 degrees.

Let's define the two angles as \( x \) and \( y \), where:

  1. \( x - y = 50 \) (the difference of the angles)
  2. \( x + y = 180 \) (the sum of the angles)

Now, we can solve these two equations.

From the first equation, we can express \( x \) in terms of \( y \):

\[ x = y + 50 \]

Now we can substitute this expression for \( x \) in the second equation:

\[ (y + 50) + y = 180 \]

Simplifying this gives:

\[ 2y + 50 = 180 \]

Subtracting 50 from both sides:

\[ 2y = 130 \]

Dividing by 2:

\[ y = 65 \]

Now, substituting \( y \) back into the equation for \( x \):

\[ x = y + 50 = 65 + 50 = 115 \]

Thus, the two angles are:

  • \( x = 115^\circ \)
  • \( y = 65^\circ \)

Therefore, the angles are \( 115 \) degrees and \( 65 \) degrees.