Question
If a function has rate of change one half
and yequals11 when xequals2, write its equation.
and yequals11 when xequals2, write its equation.
Answers
GPT-4o mini
To find the equation of a linear function based on the information provided, we can use the point-slope form of a linear equation, which is given by:
\[
y - y_1 = m(x - x_1)
\]
where \(m\) is the rate of change (slope), and \((x_1, y_1)\) is a point on the line.
Given:
- Rate of change (slope) \(m = \frac{1}{2}\)
- Point \((x_1, y_1) = (2, 11)\)
We can substitute these values into the point-slope form:
\[
y - 11 = \frac{1}{2}(x - 2)
\]
Now, we simplify this equation:
\[
y - 11 = \frac{1}{2}x - 1
\]
Now, adding 11 to both sides:
\[
y = \frac{1}{2}x - 1 + 11
\]
\[
y = \frac{1}{2}x + 10
\]
Thus, the equation of the function is:
\[
y = \frac{1}{2}x + 10
\]
\[
y - y_1 = m(x - x_1)
\]
where \(m\) is the rate of change (slope), and \((x_1, y_1)\) is a point on the line.
Given:
- Rate of change (slope) \(m = \frac{1}{2}\)
- Point \((x_1, y_1) = (2, 11)\)
We can substitute these values into the point-slope form:
\[
y - 11 = \frac{1}{2}(x - 2)
\]
Now, we simplify this equation:
\[
y - 11 = \frac{1}{2}x - 1
\]
Now, adding 11 to both sides:
\[
y = \frac{1}{2}x - 1 + 11
\]
\[
y = \frac{1}{2}x + 10
\]
Thus, the equation of the function is:
\[
y = \frac{1}{2}x + 10
\]