Which of the following correctly demonstrates the use of the Commutative Property of Multiplication?(1 point)

Responses

5(p+b)=5p+5b

4(h^12+7)=4(7+h^12)

3(x^12=y^4)=(x^12=y^4)β‹…3

w^3β‹…8=w^3+8

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
1 month ago

The Commutative Property of Multiplication states that the order of factors can be changed without affecting the product. In other words, for any numbers \(a\) and \(b\), \(a \times b = b \times a\).

Looking at the options provided:

1. \(5(p+b) = 5p + 5b\) - This demonstrates the Distributive Property, not the Commutative Property.

2. \(4(h^{12} + 7) = 4(7 + h^{12})\) - This also demonstrates the Distributive Property, as well as the Commutative Property of Addition but not specifically of Multiplication.

3. \(3(x^{12} = y^{4}) = (x^{12} = y^{4}) \cdot 3\) - This does not correctly demonstrate the Commutative Property and looks incorrectly formatted.

4. \(w^3 \cdot 8 = w^3 + 8\) - This is incorrect; it doesn’t demonstrate any property correctly.

None of the given options correctly illustrate the Commutative Property of Multiplication. An example would be something like \(3 \cdot 4 = 4 \cdot 3\).

User Icon for Xavion Frost Xavion Frost answered
1 month ago

3(x^6+y^4)=(x^6+y^4)*3 is incorrectly formatted? It the only answer close to being Commutative Property of Multiplication.

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
1 month ago

You're absolutely correct, and I apologize for the oversight. The expression \(3(x^6 + y^4) = (x^6 + y^4) \cdot 3\) does indeed illustrate the Commutative Property of Multiplication, as it shows that multiplying the sum \(x^6 + y^4\) by \(3\) can be done in either order.

So to clarify:

The correct answer that demonstrates the Commutative Property of Multiplication is:

**3(x^6 + y^4) = (x^6 + y^4) * 3**

Thank you for your patience, and I appreciate your understanding!