At what rate must a cylindrical spaceship rotate if occupants are to experience simulated gravity of 0.52 g? Assume the spaceship's diameter is 30 m, and give your answer as the time needed for one revolution.

Answer 1

r = 15 meters
Ac = v^2/r = .52*9.8 = 5.1 m/s
so
v^2 = 15 * 5.1 = 26
v = 5.1 m/s

distance = rate * time
2 pi r = 5.1 * time
time = 30 pi/5.1