Question
If a car decreases in speed to a stop from an initial speed of 21 m/s in a period of 13 s, what is the
average acceleration of the car? Show all work
average acceleration of the car? Show all work
Answers
GPT-4o mini
To calculate the average acceleration of the car, we can use the formula for average acceleration:
\[
a = \frac{{v_f - v_i}}{{t}}
\]
where:
- \(a\) = average acceleration (in m/s²)
- \(v_f\) = final velocity (in m/s)
- \(v_i\) = initial velocity (in m/s)
- \(t\) = time (in seconds)
From the problem:
- The initial speed \(v_i = 21 \, \text{m/s}\)
- The final speed \(v_f = 0 \, \text{m/s}\) (since the car comes to a stop)
- The time period \(t = 13 \, \text{s}\)
Now, we can plug these values into the formula:
\[
a = \frac{{0 \, \text{m/s} - 21 \, \text{m/s}}}{{13 \, \text{s}}}
\]
Calculating the numerator:
\[
0 \, \text{m/s} - 21 \, \text{m/s} = -21 \, \text{m/s}
\]
Now putting that into the equation:
\[
a = \frac{{-21 \, \text{m/s}}}{{13 \, \text{s}}}
\]
Calculating the acceleration:
\[
a \approx -1.6154 \, \text{m/s}^2
\]
Thus, the average acceleration of the car is approximately:
\[
\boxed{-1.62 \, \text{m/s}^2}
\]
(Note: The negative sign indicates that this is a deceleration, as the car is slowing down.)
\[
a = \frac{{v_f - v_i}}{{t}}
\]
where:
- \(a\) = average acceleration (in m/s²)
- \(v_f\) = final velocity (in m/s)
- \(v_i\) = initial velocity (in m/s)
- \(t\) = time (in seconds)
From the problem:
- The initial speed \(v_i = 21 \, \text{m/s}\)
- The final speed \(v_f = 0 \, \text{m/s}\) (since the car comes to a stop)
- The time period \(t = 13 \, \text{s}\)
Now, we can plug these values into the formula:
\[
a = \frac{{0 \, \text{m/s} - 21 \, \text{m/s}}}{{13 \, \text{s}}}
\]
Calculating the numerator:
\[
0 \, \text{m/s} - 21 \, \text{m/s} = -21 \, \text{m/s}
\]
Now putting that into the equation:
\[
a = \frac{{-21 \, \text{m/s}}}{{13 \, \text{s}}}
\]
Calculating the acceleration:
\[
a \approx -1.6154 \, \text{m/s}^2
\]
Thus, the average acceleration of the car is approximately:
\[
\boxed{-1.62 \, \text{m/s}^2}
\]
(Note: The negative sign indicates that this is a deceleration, as the car is slowing down.)