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Original Question
Find the numerical equivalent of 10^2 ⋅10^3 A.1,100 B.10 C.100,000 D.10^5Question
Find the numerical equivalent of 10^2 x 10^3
1,100
10
100,000
10^5
1,100
10
100,000
10^5
Answers
Answer
are you sure its not 100,000
Answer
yeah you cant do math
Answered by
GPT-4o mini
To find the numerical equivalent of \(10^2 \times 10^3\), you can use the property of exponents which states that when you multiply numbers with the same base, you add their exponents:
\[
10^2 \times 10^3 = 10^{2+3} = 10^5
\]
So the numerical equivalent of \(10^2 \times 10^3\) is \(10^5\).
The answer is: \(10^5\).
\[
10^2 \times 10^3 = 10^{2+3} = 10^5
\]
So the numerical equivalent of \(10^2 \times 10^3\) is \(10^5\).
The answer is: \(10^5\).
Answered by
GPT-4o mini
Yes, I am sure about the relationship between \(10^5\) and its numerical equivalent.
While \(10^5\) is the exponential form, its numerical equivalent is, in fact, \(100,000\).
So, to clarify:
- \(10^5\) is equal to \(100,000\).
- The answer to the original question asking for the result of \(10^2 \times 10^3\) is indeed \(10^5\), which is also \(100,000\) in numerical form.
If you're looking for the numerical value, then you'd say it’s \(100,000\). Thank you for your patience!
While \(10^5\) is the exponential form, its numerical equivalent is, in fact, \(100,000\).
So, to clarify:
- \(10^5\) is equal to \(100,000\).
- The answer to the original question asking for the result of \(10^2 \times 10^3\) is indeed \(10^5\), which is also \(100,000\) in numerical form.
If you're looking for the numerical value, then you'd say it’s \(100,000\). Thank you for your patience!
Answered by
GPT-4o mini
I apologize for any confusion earlier. My initial response was focused on the exponentiation of the expression, which resulted in \(10^5\). However, you are correct that if you are looking for the numerical equivalent, \(10^5 = 100,000\).
Thank you for pointing that out, and I appreciate your understanding. If you have any more questions or need further assistance, feel free to ask!
Thank you for pointing that out, and I appreciate your understanding. If you have any more questions or need further assistance, feel free to ask!
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