Solve the following equation: 3(x−2)=81

. What is the missing value

7 answers

To solve the equation \( 3(x - 2) = 81 \), follow these steps:

  1. Divide both sides of the equation by 3:

\[ x - 2 = \frac{81}{3} \]

  1. Calculate \( \frac{81}{3} \):

\[ x - 2 = 27 \]

  1. Now add 2 to both sides of the equation:

\[ x = 27 + 2 \]

  1. Calculate \( 27 + 2 \):

\[ x = 29 \]

Thus, the missing value is \( x = 29 \).

the x and the 2 are x+2^

If the equation is \(3(x + 2) = 81\), let's solve it step by step:

  1. Start with the equation:

    \[ 3(x + 2) = 81 \]

  2. Divide both sides by 3:

    \[ x + 2 = \frac{81}{3} \]

  3. Calculate \( \frac{81}{3} \):

    \[ x + 2 = 27 \]

  4. Now, subtract 2 from both sides:

    \[ x = 27 - 2 \]

  5. Calculate \( 27 - 2 \):

    \[ x = 25 \]

Thus, the missing value is \( x = 25 \).

Using the properties of exponents, which expression is equivalent to x16⋅x16?(1 point)
Responses

x−−√36
root index 36 Start Root x End Root

x−−√
Start Root x End Root

x−−√3
root index 3 Start Root x End Root

1x√3

To simplify the expression \( x^{16} \cdot x^{16} \) using the properties of exponents, we can use the property that states that when you multiply two expressions with the same base, you add the exponents:

\[ x^{a} \cdot x^{b} = x^{a+b} \]

In this case:

\[ x^{16} \cdot x^{16} = x^{16 + 16} = x^{32} \]

Now, we can express \( x^{32} \) in terms of a root. The expression \( x^{32} \) can be rewritten as:

\[ x^{32} = \left( x^{\frac{1}{32}} \right)^{32} = x^{\frac{32}{32}} = x^{1} = x \]

However, if the responses you provided focus on roots instead, we can also express \( x^{32} \) in terms of a root with an appropriate index:

\[ x^{32} = \sqrt[32]{x^{64}} \quad \text{(for example)} \]

Given the options you provided:

  1. \( \sqrt[36]{x} \)
  2. \( \sqrt{x} \)
  3. \( \sqrt[3]{x} \)
  4. \( \frac{1}{x \sqrt{3}} \)

None of these expressions directly match \( x^{32} \). However, based on the context, if we simplify for \( x^{16} \), we could consider only the resultant formats derived from roots.

Conclusion:

If you want a specific match, please provide any missing context or clarify how to relate \( x^{32} \) back to root expressions further, or refer to the closest resemblance based on the provided options since they don't align exactly with \( x^{32} \).

its x 1/6 x x 1/6 sorry

Thank you for the clarification! If you're looking to simplify the expression \( x^{1/6} \cdot x^{1/6} \), we can use the properties of exponents.

Using the property \( a^m \cdot a^n = a^{m+n} \), we can combine the exponents:

\[ x^{1/6} \cdot x^{1/6} = x^{1/6 + 1/6} = x^{2/6} = x^{1/3} \]

Now, \( x^{1/3} \) can also be expressed in terms of a root as:

\[ x^{1/3} = \sqrt[3]{x} \]

Conclusion:

The equivalent expression for \( x^{1/6} \cdot x^{1/6} \) is \( \sqrt[3]{x} \).

From your options, the correct response is:

  • \( \sqrt[3]{x} \) (which corresponds to the option \( \sqrt[3]{x} \)).